The Find operation in Disjoint Set Abstract Data Type (ADT) is crucial for determining the representative of the set containing a particular element. It assists in checking if two elements are in the same set and is often used in union-find algorithms.
class DisjointSet {
int[] parent;
public DisjointSet(int n) {
parent = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
}
}
public int find(int x) {
if (parent[x] != x) {
return find(parent[x]);
}
return x;
}
}
In this basic implementation, the find operation recursively traverses the parent array until it finds the root of the set. This root is the representative of the set.
class DisjointSet {
int[] parent;
public DisjointSet(int n) {
parent = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
}
}
public int find(int x) {
if (parent[x] != x) {
parent[x] = find(parent[x]);
}
return parent[x];
}
}
Path compression is an optimization that flattens the structure of the tree whenever find is called, making future queries faster by directly linking nodes to the root.
class DisjointSet {
int[] parent, rank;
public DisjointSet(int n) {
parent = new int[n];
rank = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
rank[i] = 0;
}
}
public int find(int x) {
if (parent[x] != x) {
parent[x] = find(parent[x]);
}
return parent[x];
}
}
In union by rank, the tree with the smaller rank is attached under the root of the tree with the larger rank. The find operation remains the same but benefits from the balanced trees created by union by rank.
class DisjointSet {
int[] parent, size;
public DisjointSet(int n) {
parent = new int[n];
size = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
size[i] = 1;
}
}
public int find(int x) {
if (parent[x] != x) {
parent[x] = find(parent[x]);
}
return parent[x];
}
}
Union by size attaches the smaller tree under the larger tree, which helps in keeping the trees shallow. The find operation benefits from this as it reduces the path length.
class DisjointSet {
int[] parent;
public DisjointSet(int n) {
parent = new int[n];
for (int i = 0; i < n; i++) {
parent[i] = i;
}
}
public int find(int x) {
while (parent[x] != x) {
x = parent[x];
}
return x;
}
}
This example demonstrates an iterative approach to the find operation, which avoids recursion and may be preferred in environments with limited stack space.
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